TypeError: Arguments to path.join must be strings    at f (path.js:204:15)    at Object.filter (native)    at exports.join (path.js:209:40)    at exports.send (E:\nodejs\demo\socket.io-express\node_modules\express\node_modules\connect\lib\middleware\static.js:129:20)    at ServerResponse.res.sendfile (E:\nodejs\demo\socket.io-express\node_modules\express\lib\response.js:186:3)    at io.sockets.on.socket.emit.text (E:\nodejs\demo\socket.io-express\app.js:8:6)    at callbacks (E:\nodejs\demo\socket.io-express\node_modules\express\lib\router\index.js:272:11)    at param (E:\nodejs\demo\socket.io-express\node_modules\express\lib\router\index.js:246:11)    at pass (E:\nodejs\demo\socket.io-express\node_modules\express\lib\router\index.js:253:5)    at Router._dispatch (E:\nodejs\demo\socket.io- express\node_modules\express\lib\router\index.js:280:5)

Node.js中的两个模块Socket.io 和Express做整合的时候出现了下面的错误：

var express = require('express');var app = module.exports = express.createServer(),    io = require('socket.io').listen(app); app.listen(3000); app.get('/', function(req, res){    res.sendfile(__dirname + '/index.html');}); io.sockets.on('connection', function(socket){    socket.emit('welcome', {text: 'OH HAI! U R CONNECTED!'});});

错误原因：

基本的错误原因是上面代码第8行，将代码改为下面形式就可以工作。

var express = require('express');var app = module.exports = express.createServer(),    io = require('socket.io').listen(app);app.listen(3000);app.get('/', function(req, res){	res.sendfile('/index.html', {root: __dirname});});io.sockets.on('connection', function(socket){	socket.emit('welcome', {text: 'OH HAI! U R CONNECTED'});});

在win 下 传

__dirname + '/index.html' -> E:\nodejs\demo/index.html

貌似,那里用 url 解析模块.最后解析的结果不是windows 那种路径样子..

然后到创建流的时候路径就不正确了..

參考资料：